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m.c.delta t = m.c.delta t
200.1.(tc-20) = 300.1.(90-tc)
200(tc-20) = 300(90-tc)
200tc-4000 = 27000-300tc
200tc+300tc= 4000+27000
500tc= 31000
tc=31000:500
tc=62°c
t1=20°C
m1=200 gr
t2=90°C
m2=300 gr
Ditanya: tc=....?
Jawab:
tc= (m1.t1) + (m2.t2) : (m1+m2)
tc=(200.20) + (300.90) : (200+300)
tc=4.000+27.000 : 500
tc=31.000:500
tc=62°C.