Question

Air bersuhu 20 C dengan massa 200 gram dicampur dengan air bersuhu 90 C bermassa 300 gram. Tentukan suhu akhir campuran!

Answer 1

Diketahui : massa air 1(ma 2) = 200 gram
suhu air (t) = 20°C
suhu air (t) = 90°C
massa air 2(ma 2) = 300 gram
Ditanya : suhu akhir campuran (t) =.......?
jawab :
ma1 × ca1 × t1 = ma2 × ca2 × t2
200 x 1 × (20 - t) = 300 x 1 × (t - 90)
4000 - 200t = 300t - 27000
-200t - 300t = - 27000 - 4000
-500t = -31000
t = 62°C