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*n H2SO4 = 100 mL x 0,1 M = 10 mmol
*n NaOH = 10 mL x 0,1 M = 1 mmol
H2SO4 + 2NaOH --> Na2SO4 + 2H2O
m 10 1
b -0,5 -1
s 9,5 -
M tot = mmol sisa/volume total (mL)
= 9,5 mmol/110 mL
= 0,08 M H2SO4
[H+] = M x valensi asam
= 0,08 x 2
= 0,16
= 1,6 x 10^-1
pH = 1 - log 1,6