Jawaban:
diket : sisi²nya 6 cm
sisi tegaknya 10 cm
ditanya : Luas....?
dijawab : akar 6²+10²= 36+100
=136
=
[tex] \sqrt{68 \times 2} [/tex]
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Jawaban:
diket : sisi²nya 6 cm
sisi tegaknya 10 cm
ditanya : Luas....?
dijawab : akar 6²+10²= 36+100
=136
=
[tex] \sqrt{68 \times 2} [/tex]