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(dipangkatkan dua di kedua ruas)
10x - x^2 < (x+2)^2
10x - x^2 < x^2 + 4x + 4
-x^2 - x^2 + 10x - 4x < 4
-2x^2 + 6x - 4 < 0
(dikali -1 dan dijadikan persamaan)
2x^2 - 6x + 4 = 0
(2x - 4)(2x -2) = 0
(x - 2)(x - 1) = 0
x1 = 2 dan x2 = 1
(karena tandanya <, jadi:)
x < 1 dan x > 2