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garis A (-2, 3) dirotasikan [O, -90 derajat] ⇔ A' (3, 2) dilatasi [O, -1] ⇒ A'' (3×-1, 2×-1)
A'' (-3, -2)
garis B (1, -5) dirotasikan [O, -90 derajat] ⇔ B' (-5, -1) dilatasi [O, -1] ⇒ B'' (-5×-1, -1×-1)
B'' (5, 1)
jadi titik A adalah A'' (-3, -2)
jadi titik B adalah B'' (5, 1)