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-2 ≤ x² - 2x - 1 ≤ 2
Sehingga, masalah 1.
-2 ≤ x² - 2x - 1
x² - 2x + 1 ≥ 0
(x-1)² ≥ 0
Dipenuhi untuk seluruh bilangan real.
Maslaah 2.
x² - 2x - 1 ≤ 2
x² - 2x - 3 ≤ 0
(x+1)(x-3) ≤ 0
Selesaian:
-1 ≤ x ≤ 3
Ambil irisan masalah 1 dengan masalah 2.
Didapat:
HP = {-1 ≤ x ≤ 3, x E R}