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y = 1/(x + 2)
xy + 2y = 1
xy = 1 - 2y
x = (1 - 2y)/y
f^-1(x) = (1 - 2x)/x
-4 = (1 - 2x)/x
-4x = 1 - 2x
-2x = 1
x = -1/2
Misalkan
y = 1 / (x + 2)
xy + 2y = 1
xy = 1 - 2y
x = (1-2y) / y
Krna sudh ditmukan pers dlm bntuk x maka invers fx adl
f^-1(x) = (1-2x)/x
Diketahui f^-1(x) = 4 maka
4 = (1-2x)/x
4x = 1 -2x >> 6x = 1
x = 1/6
Jdi nilai x adl 1/6
Smoga mmbntu dn mudh dpahami
#FunWithMath