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g(x+1) = 2x-1
Dan,
Fungsi komposisinya adalah:
f(g(x+1)) = 2x + 4
Maka,
f(2x-1) = 2x + 4
Maka,
f(2x) = 2(x+1) + 4
f(x) = 2(1/2 (x+1) ) + 4
f(x) = x+1 + 4
f(x) = x + 5
Sehingga, didapatkan:
f(0) = 0 + 5
f(0) = 5