Question

Ada yang bisa bantu​

Answer 1

Verified answer

Jawab:

1) grafik  trignometr

nilai maksimum ,  dengan simpangan terjauh

di x  = 4

2)  m = y' = - 4x

y = ∫y' dx = ∫ -4x dx

y = -2x² + c  .melalui Q(2, 42)

c = y + 2x²

c = 42 + 2(2)²

c = 50

y = -2x² + 50

y' = 0 --> 4x = 0

x = 0 -> y = 50

x= a= 0 , y = b= 50

3a + b =  3(0) + (50)

3a + b = 50