Jawab:
1) grafik trignometr
nilai maksimum , dengan simpangan terjauh
di x = 4
2) m = y' = - 4x
y = ∫y' dx = ∫ -4x dx
y = -2x² + c .melalui Q(2, 42)
c = y + 2x²
c = 42 + 2(2)²
c = 50
y = -2x² + 50
y' = 0 --> 4x = 0
x = 0 -> y = 50
x= a= 0 , y = b= 50
3a + b = 3(0) + (50)
3a + b = 50
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Jawab:
1) grafik trignometr
nilai maksimum , dengan simpangan terjauh
di x = 4
2) m = y' = - 4x
y = ∫y' dx = ∫ -4x dx
y = -2x² + c .melalui Q(2, 42)
c = y + 2x²
c = 42 + 2(2)²
c = 50
y = -2x² + 50
y' = 0 --> 4x = 0
x = 0 -> y = 50
x= a= 0 , y = b= 50
3a + b = 3(0) + (50)
3a + b = 50