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= - sin² x + 3 sin x + 10
fungsi minimum when f'(x) = 0
- 2 sin x cos x + 3 cos x = 0
cos x (-2 sin x + 3) = 0
cos x = 0 and - 2sin x = -3
sin x = 3/2 --> NA
cos x = 0
cos x = cos 90, cos 270
x = 90, 270
f(90) = (2 + sin 90) (5 - sin 90)
= (2+1) (5-1)
= 12
f(270) = (2 + sin 270) ( 5 - sin 270)
= (2 - 1) ( 5+1)
= 6
minimum f(x) = 6
3. x + 2y = 1
x - y = -2
---------------- -
3y = 3
y = 1, --> x = -2+y
= -1
meet at (-1,1)
ax - y + 3 = 0
a(-1) - 1 + 3 = 0
-a + 2 = 0
-a = -2
a = 2