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Absis titk balik = x simetris
x simetris = -b/2a
jika absis titik balik adalah p
maka
p = -b/2a, lihat pers f(x) --> a = p, b =p-3
p= -(p-3) / 2p
2p² = -p+3
2p²+p-3=0
(2p + 3)(p - 1) = 0
2p+3 = 0 atau p-1 = 0
p = -3/2 atau p =1