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[tex] \frac{6}{ \sqrt{7} + 2} = \frac{6}{ \sqrt{7} + 2 } \times \frac{ \sqrt{7} - 2}{ \sqrt{7} - 2 } [/tex]
[tex]~~~~~~~~~~= \frac{6( \sqrt{7} - 2) }{7 - 4} [/tex]
[tex]~~~~~~~~~~= \frac{6 \sqrt{7} - 12 }{3} [/tex]
[tex]~~~~~~~~~~=2 \sqrt{7} - 4[/tex]
[tex]\begin{array}{lr}\texttt{Selamat Menunaikan Ibadah Puasa}\end{array}[/tex]
[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alf'at | 28 - 03 - 2023}}[/tex]
6/√7 + 2
= 6/√7 + 2 × √7 - 2/√7 - 2
= 6(√7 - 2)/(√7 + 2(√7 - 2)
= 6(√7 - 2)/(√7(√7)(-2(2)
= 6(√7 - 2)/7 - 4
= 6(√7 - 2)/3
= (6/3)(√7 - 2)
= 2(√7 - 2)
= (2(√7) - (2(2)
= 2√7 - 4
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Merasionalkan Akar
..
[tex] \frac{6}{ \sqrt{7} + 2} = \frac{6}{ \sqrt{7} + 2 } \times \frac{ \sqrt{7} - 2}{ \sqrt{7} - 2 } [/tex]
[tex]~~~~~~~~~~= \frac{6( \sqrt{7} - 2) }{7 - 4} [/tex]
[tex]~~~~~~~~~~= \frac{6 \sqrt{7} - 12 }{3} [/tex]
[tex]~~~~~~~~~~=2 \sqrt{7} - 4[/tex]
..
[tex]\begin{array}{lr}\texttt{Selamat Menunaikan Ibadah Puasa}\end{array}[/tex]
[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alf'at | 28 - 03 - 2023}}[/tex]
6/√7 + 2
= 6/√7 + 2 × √7 - 2/√7 - 2
= 6(√7 - 2)/(√7 + 2(√7 - 2)
= 6(√7 - 2)/(√7(√7)(-2(2)
= 6(√7 - 2)/7 - 4
= 6(√7 - 2)/3
= (6/3)(√7 - 2)
= 2(√7 - 2)
= (2(√7) - (2(2)
= 2√7 - 4