Question

Pelajaran Trigonometri(nilai-nilai perbandingan).Bantu y kk/abg

Answer 1

Verified answer

∆PTQ
PTQ = 30°
sin PTQ = PQ/PT

PT = PQ/sin 30°
PT = 6 × 2
PT = 12 cm ✓

tan PTQ = PQ/QT
QT = PQ/tan 30°
QT = 6 × √3
QT = 6√3 cm ✓

Luas bangun
= luas ∆PQT + luas ∆SQR
= 1/2 . PQ . QT + 1/2 . SQ . QR
= 1/2 . 6 . 6√3 + 1/2 . (6√3 - 4) . 5
= 18√3 + 5(3√3 - 2)
= 18√3 + 15√3 - 10
= (33√3 - 10) cm²