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CE : CB = 3 : 5 ⇔ CE : (CE + BE) = 3 : 5
⇔ CE : (CE + 8) = 3Δ : 5Δ
Selisih nya dari kedua ruas 8 cm = 2Δ
CD = 3
CA = 5
BE = 8
ditanya : CE...?
jawab :
• (CD/CA) = (CE/CB)
• (3/5) = (x/[8+x])
• 3(8+x) = 5(x)
• 24+3x = 5x
• 5x -3x = 24
• 2x = 24
• x = 12 cm
panjang CE = 12 cm