Question

a)216y³+108y²+18y+1

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Answer 1

Verified answer

RESPUESTA:

[tex]216y^3+108y^2+18y+1[/tex]

[tex]\left(6y+1\right)\left(36y^2+12y+1\right)[/tex]

Factorizamos :)

[tex]=\left(6y+1\right)\left(6y+1\right)\left(6y+1\right)[/tex]

[tex]\mathrm{Aplicar\:las\:leyes\:de\:los\:exponentes}:aaa=a^3[/tex]

[tex]\left(6y+1\right)\left(6y+1\right)\left(6y+1\right)=\left(6y+1\right)^3[/tex]

[tex]RPTA = \left(6y+1\right)^3[/tex]

【ツ】亗 CORONA 亗