Question

(a+1) x3 + (b–1) x2 + (c+2) x + d – 1 ≡
el 3 y el dos son exponentes ok

Answer 1

(a+1)x.3+(b-1)x.2+(c+2)x+d-1
=3ax+3x+(b-1)x.2+(c+2)x+d-1
=3ax+3x+2bx-2x+(c+2)x+d-1
=3ax+3x+2bx-2x+xc+x.2+d-1
=cx+3x+2bx+3ax+d-1