(a x b x c)⁴ x 3per(b x c) x b³per27a^5 ??.... Question from @Randyarsa

August 2018 2 12 Report

(a x b x c)⁴ x 3per(b x c) x b³per27a^5 ??

MathSolver74 (a⁴b⁴c⁴) x 3/(bc) x b³/(27a⁵)
= (3/27)a⁻¹b⁶c³

1 votes Thanks 2

feriboxil (a⁴b⁴c⁴) x 3/(bc) x b³/(27a⁵)
= (3/27)a⁻¹b⁶c³

0 votes Thanks 0

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