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P₁V₁ =P₂V₂
despejando se obtiene que:
P₁ = P₂V₂ / V₁
V₁ = P₂V₂ / P₁
P₂ = P₁V₁ / V₂
V₂ = P₁V₁ / P₂
Donde:
P₁= Presión Inicial P₂= Presión Final V₁= Volumen Inicial V₂= Volumen Final
P₂ = P₁V₁
V₂
se cancelan los litros
P₂ = 17 atm . 34 lts ⇒ 578 atm.lts ⇒ P₂ = 38,5 atm
15 lts 15 lts
porfa, calificame...gracias..