a. Oblicz skład proc Benzenu (%masowy)
b. zapisz reakcję spalania całkowitego Benzenu
C6H6
%C = 72/78 = 92,3%
%H = 6/78 = 7,7%
2 C6H6 + 15 O2 = 12 CO2 + 6 H2O
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C6H6
%C = 72/78 = 92,3%
%H = 6/78 = 7,7%
2 C6H6 + 15 O2 = 12 CO2 + 6 H2O