Question

a. Jika P(x) = 2x³ - 3x² + x+7, hitung p(2), p(0) dan p(-2)

b. jika p (x) = 2x³+x²-3x+4, hitung p (3), p(0) dan p(-3)​

Answer 1

Jawaban:

a. Menggunakan fungsi P(x) = 2x³ - 3x² + x + 7

1. Menghitung P(2)

P(2) = 2(2)³ - 3(2)² + 2 + 7

= 2(8) - 3(4) + 2 + 7

= 16 - 12 + 2 + 7

= 21

2. Menghitung P(0)

P(0) = 2(0)³ - 3(0)² + 0 + 7

= 0 - 0 + 0 + 7

= 7

3. Menghitung P(-2)

P(-2) = 2(-2)³ - 3(-2)² - 2 + 7

= 2(-8) - 3(4) - 2 + 7

= -16 - 12 - 2 + 7

= -23

b. Menggunakan fungsi P(x) = 2x³ + x² - 3x + 4

1. Menghitung P(3)

P(3) = 2(3)³ + 3² - 3(3) + 4

= 2(27) + 9 - 9 + 4

= 54 + 9 - 9 + 4

= 58

2. Menghitung P(0)

P(0) = 2(0)³ + 0² - 3(0) + 4

= 0 + 0 - 0 + 4

= 4

3. Menghitung P(-3)

P(-3) = 2(-3)³ + (-3)² - 3(-3) + 4

= 2(-27) + 9 + 9 + 4

= -54 + 9 + 9 + 4

= -32