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b = 3+a ec. 2
Sustituyendo valores de la ec. 2 en la ec. 1:
2a + 2*(3+a) = 26
2a + 6 + 2a = 26
4a + 6 = 26
4a = 26-6
4a = 20
a = 20/4
a = 5
De la ec. 2:
b = 3+a
b = 5+3
b = 8
Comprobémoslo en la ec. 1:
2a+2b = 26
2*5 + 2*8 = 26
10+16 = 26 comprobado.
Por tanto las dimensiones de los lados del cuadrado son:
altura = 5 cm
base = 8 cm
Saludos..........