oblicz mase molowa/
a) chlorek(1wartościowy) wodoru (1)
b) tlenek(2) antymonu (5)
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oblicz mase molowa/
a) chlorek(1wartościowy) wodoru (1)
b) tlenek(2) antymonu (5)
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a) HCl Mhcl= 1g/mol + 35,5g/mol=36,5 g/mol
b)Sb2O5 Msb2o5= 2*121,8 g/mol+ 5*16 g/mol= 243,6 + 80= 323,6g/mol
a) HCl Mhcl= 1g_mol + 35,5g_mol=36,5 g_mol
b)Sb2O5 Msb2o5= 2*121,8 g_mol+ 5*16 g_mol= 243,6 + 80= 323,6g_mol