Jawaban:
<abd = 62°
Ditanya <bcd
<abd = <dbc = 62°
Segitiga siku" b, c, dan titik tengah:
180° - (90°+62°) = 180 - 152 = 28°
<bcd = 2 x 28° = 56°
C. 56°
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Jawaban:
<abd = 62°
Ditanya <bcd
<abd = <dbc = 62°
Segitiga siku" b, c, dan titik tengah:
180° - (90°+62°) = 180 - 152 = 28°
<bcd = 2 x 28° = 56°
C. 56°
Semoga membantu, maaf jika ada kesalahan