December 2019 1 16 Report
 \frac{ {p}^{0} \times \: {p}^{2n + 1} \times {p}^{3n - 2} }{ {p}^{n + 5} } =
A.
 {p}^{6n - 4}
B.
 {p}^{4n - 4}
C.
 {p}^{6n - 6}
D.
 {p}^{4n - 6}



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