Question

1._Hallar el valor de :
[tex]( - 2) ^{3} + (3)^{2} [/tex]

2._Se sabe que A=
[tex] {2}^{3} \times {2}^{4} [/tex]
B=
[tex]( {2}^{2} )^{5} \times (4)^{3} [/tex]
hallar P= B/A



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Answer 1

Verified answer

Explicación paso a paso:

[tex] {( -2 )}^{3} + {(3)}^{2} \\ - 8 + 9 \\ 1[/tex]

[tex]a = {2}^{3} \times {2}^{4} \\ a = 8 \times 16 \\ a = 128[/tex]

[tex]b = ( {2}^{2})^{5} \times {4}^{3} \\ b = 1024 \times 64 \\ b = 65536[/tex]

[tex]p = \frac{b}{a} \\ p = \frac{65536}{128} \\ p = 512[/tex]