Question

A) 5(a+1)=10
B) 0,5(4t-10) = 2(t + 5 )
C) 3(2z - 1 ) + 1 = -2 (2z + 9 )

Answer 1

A)
5a+5 = 10
5a = 10-5
5a = 5
a = 5/5
a = 1


b)
2t-5 = 2t+10
2t-2t = 10+5
0 = 15


c)
6z-3+1 = -4z-18
6z-2 = -4z-18
6z+4z = -18+2
10z = -16
z = -16/10
z = -1 6/10
z = -1 3/5

Answer 2

A) 5 (a + 1) = 10
5a + 5 = 10
5a = 10 - 5
5a = 5
a = 5/5
a = 1

b) 0,5 (4t - 10) = 2 (t + 5)
2t - 5 = 2t + 10
2t - 2t = 10 + 5
0 = 15

c) 3 (2z - 1) + 1 = -2 (2z + 9)
6z - 3 + 1 = -4z - 18
6z + 4z = -18 + 3 - 1
10z = -16
z = -16/10 <=== sampai disini tdk masalah
z = -1,6 atau -1 3/5