Jawab:Nilai p = 6
Penjelasan :Diketahui: a + 1/a = 10 (pers i)a - 1/a = 4√p (pers ii)
Ditanya: nilai p
a + 1/a = 10 (pers i)1/a = 10 - a
a - 1/a = 4√p (pers ii)a - (10 - a) = 4√pa - 10 + a = 4√pa + a = 10 + 4√p2a = 10 + 4√p (pers iii)
Cari nilai a dari a + 1/a = 10(a²/a) + (1/a) = (10a/a)a² - 10a = -1a² - 2a(10/2) + (10/2)² = -1 + (10/2)²∵ p² - 2pq + q² = (p-q)² ∴(a - 10/2)² = -1 + (10/2)²(a - 5)² = -1 + 5²(a - 5)² = -1 + 25(a - 5)² = 24| a - 5 | = √24| a - 5 | = √(4·6)| a - 5 | = √4√6| a - 5 | = 2√6a = 5±2√6
Dari 2a = 10 + 4√p (pers iii)2(5±2√6) = 10 + 4√p10 ± 4√6 = 10 + 4√p
Untuk 10+4√6 = 10 + 4√pp = 6
Dan untuk 10-4√6 = 10 + 4√p-4√6 = 4√p√p = -√6Tidak ada solusi
Nilai p = 6(xcvi)
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Jawab:
Nilai p = 6
Penjelasan :
Diketahui:
a + 1/a = 10 (pers i)
a - 1/a = 4√p (pers ii)
Ditanya: nilai p
a + 1/a = 10 (pers i)
1/a = 10 - a
a - 1/a = 4√p (pers ii)
a - (10 - a) = 4√p
a - 10 + a = 4√p
a + a = 10 + 4√p
2a = 10 + 4√p (pers iii)
Cari nilai a dari
a + 1/a = 10
(a²/a) + (1/a) = (10a/a)
a² - 10a = -1
a² - 2a(10/2) + (10/2)² = -1 + (10/2)²
∵ p² - 2pq + q² = (p-q)² ∴
(a - 10/2)² = -1 + (10/2)²
(a - 5)² = -1 + 5²
(a - 5)² = -1 + 25
(a - 5)² = 24
| a - 5 | = √24
| a - 5 | = √(4·6)
| a - 5 | = √4√6
| a - 5 | = 2√6
a = 5±2√6
Dari 2a = 10 + 4√p (pers iii)
2(5±2√6) = 10 + 4√p
10 ± 4√6 = 10 + 4√p
Untuk 10+4√6 = 10 + 4√p
p = 6
Dan untuk 10-4√6 = 10 + 4√p
-4√6 = 4√p
√p = -√6
Tidak ada solusi
Nilai p = 6
(xcvi)