Question

A) ( 3a-b-c+2)+(2a+3b+5c-7)+(6a-4b+3c-2)
B) (2ײ -3×-5)+(×2+6×+8)+(7ײ-9×-4)
C) (4׳-6×+8)+(3ײ+5×-7)+(2׳-ײ-3×+9)
D) (2ab-3c+d-1)+(4ab+7c-3d)+(-c+4d+2)
E) (8r-2s+t+1)+(5s-2r-3t+7)+(5r-4)
f) (2.5x+3.8y)+(5.1x+3.2y)
g) (4.3a-0.5b)+(0.7a+2.5b)
h) (2.8a-1.3b+4c)+(a-b-0.5c)​

Answer 1

Verified answer

Explicación paso a paso:

A)

( 3a-b-c+2)+(2a+3b+5c-7)+(6a-4b+3c-2)=

3a-b-c+2+2a+3b+5c-7+6a-4b+3c-2=

3a+2a+6a-b+3b-4b-c+5c+3c+2-7-2=

11a-2b+7c-7

B)

(2ײ -3×-5)+(ײ+6×+8)+(7ײ-9×-4)=

2ײ -3×-5+ײ+6×+8+7ײ-9×-4=

2x²+x²+7x²-3x+6x-9x-5+8-4=

10x²-6x-1

C)

(4׳-6×+8)+(3ײ+5×-7)+(2׳-ײ-3×+9)=

4׳-6×+8+3ײ+5×-7+2׳-ײ-3×+9=

4x³+2x³+3x²-x²-6x+5x-3x+8-7+9=

6x³+2x²-4x+10

D)

(2ab-3c+d-1)+(4ab+7c-3d)+(-c+4d+2)=

2ab-3c+d-1+4ab+7c-3d-c+4d+2=

2ab+4ab-3c+7c-c+d-3d+4d-1+2=

6ab+3c+2d+1

E)

(8r-2s+t+1)+(5s-2r-3t+7)+(5r-4)=

8r-2s+t+1+5s-2r-3t+7+5r-4=

8r-2r+5r-2s+5s+t-3t+1+7-4=

11r+3s-2t+4

F)

2.5x+3.8y)+(5.1x+3.2y)=

2.5x+3.8y+5.1x+3.2y=

2.5x+5.1x+3.8y+3.2y=

7.6x+7y

G)

(4.3a-0.5b)+(0.7a+2.5b)=

4.3a-0.5b+0.7a+2.5b=

4.3a+0.7a-0.5b+2.5b=

5a+2b

H)

(2.8a-1.3b+4c)+(a-b-0.5c)=

2.8a-1.3b+4c+a-b-0.5c=

2.8a+a-1.3b-b+4c-0.5c=

3.8a-2.3b+3.5c