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x = a
y = 2b
z = 3c
x + y + z = 12
xy + yz + zx = 48
(x + y + z)² = x² +y² +z² +2(xy + yz + zx )
12² = x² +y² +z²+ 2(48)
144 = x² +y² +z² + 96
x² +y² +z² + 96 = 144
x² +y² +z² = 48 hal ini menyebabkan
x² +y² +z² = xy + yz + zx
x = y = z = 4
subtitusikan ke pemisalan
didapat a = 4, b = 2, c = 4/3
maka a + b + c = 4 + 2 + 4/3 = 22/3