Respuesta:
[tex]4a^{2} + 2a = \\ a(4a + 2) = 0 \\ a = 0 \\ 4a + 2 = 0 \\ 4a = - 2 \\ a = - \frac{2}{4} = - \frac{1}{2} [/tex]
Hay 2 soluciones:
a=0 a=-1/2
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Respuesta:
[tex]4a^{2} + 2a = \\ a(4a + 2) = 0 \\ a = 0 \\ 4a + 2 = 0 \\ 4a = - 2 \\ a = - \frac{2}{4} = - \frac{1}{2} [/tex]
Hay 2 soluciones:
a=0 a=-1/2