Luas arsir = Luas ∆1 + Luas Tr - 2 Luas ∆2
= a x t x ½ + jss x t x ½ - a x t
= 12 x (8+6+4) x ½ + (12+8+10) x (8+6) x ½ - 12 x 8
= 6 x 18 + 30 x 14 x ½ - 96
= 108 + 210 - 96
= 222 cm²
Jadi jawabannya B
× Mohon maaf bila ada kesalahan. Semoga membantu^^ ×
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Luas arsir = Luas ∆1 + Luas Tr - 2 Luas ∆2
= a x t x ½ + jss x t x ½ - a x t
= 12 x (8+6+4) x ½ + (12+8+10) x (8+6) x ½ - 12 x 8
= 6 x 18 + 30 x 14 x ½ - 96
= 108 + 210 - 96
= 222 cm²
Jadi jawabannya B
× Mohon maaf bila ada kesalahan. Semoga membantu^^ ×