Podaj ilość protonów, neutronów i elektronów dla 14/7N i 19/9F.
dla azotu (N)
p⁺=e⁻=7
n°=14-7=7
dla fluoru
p⁺=e⁻=9
n°=19-9=10
N:
p= 7
n= 7
e= 7
F:
p= 9
n= 10
e= 9
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dla azotu (N)
p⁺=e⁻=7
n°=14-7=7
dla fluoru
p⁺=e⁻=9
n°=19-9=10
N:
p= 7
n= 7
e= 7
F:
p= 9
n= 10
e= 9