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jika begitu : m c deltaT
= 500 . 0,5 . 12
= 3000 kal
lebur = M. L
= 500 . 80
= 40000 kal
m. c. delta T
= 500. 1 . 2
= 1000 kal
total = 3000+ 40000+ 1000
=44000 kal / 44 kkal