Question

Diketahui A+B = 90° dan cos A = 2/3 tan B. Nilai secan^2 B =
A. 9/4
B. 3/2
C. 3/4
D. 2/3
E. 2/9

Answer 1

C.3/4 maaf kalo salah

Answer 2

A + B = 90° => A = 90° - B
Cos A = 2/3 Tan B
Cos (90° - B) = 2/3 . (Sin B)/(cos B)
Sin B = 2/3 . (Sin B)/(cos B)
Sin B . (Cos B)/(sin B) = 2/3
Cos B = 2/3
Sec B = 3/2
Sec^2 B = (3/2)^2 = 9/4