9. D
f(x) =
g(x) =
→ mencari (gof)(x)
(gof)(x) = g(f(x))
= g()
=
= ( 2x - 3 ) ( 2x + 3 ) ≥ 0
2x = 3 2x = -3
x = x =
→ menentukan domain
11. E
→ mencari B
B = A - (A-B)
→ nilai
→ nilai det
14. C
sorry cuma bisa jawab 3, otak udh buntu:') udh ngantuk bangett, hehe
semoga membantu!
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9. D
f(x) =
g(x) =
→ mencari (gof)(x)
(gof)(x) = g(f(x))
= g(
)
=
=
=
= ( 2x - 3 ) ( 2x + 3 ) ≥ 0
2x = 3 2x = -3
x =
x = 
→ menentukan domain
11. E
→ mencari B
B = A - (A-B)
=![\left[\begin{array}{ccc}2&-3\\1&1\end{array}\right] - \left[\begin{array}{ccc}-1&0\\3&-2\end{array}\right] \left[\begin{array}{ccc}2&-3\\1&1\end{array}\right] - \left[\begin{array}{ccc}-1&0\\3&-2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26-3%5C%5C1%261%5Cend%7Barray%7D%5Cright%5D%20-%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1%260%5C%5C3%26-2%5Cend%7Barray%7D%5Cright%5D)
=![\left[\begin{array}{ccc}2-(-1)&-3-0\\1-3&1-(-2)\end{array}\right] \left[\begin{array}{ccc}2-(-1)&-3-0\\1-3&1-(-2)\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2-%28-1%29%26-3-0%5C%5C1-3%261-%28-2%29%5Cend%7Barray%7D%5Cright%5D)
=![\left[\begin{array}{ccc}3&-3\\-2&3\end{array}\right] \left[\begin{array}{ccc}3&-3\\-2&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-3%5C%5C-2%263%5Cend%7Barray%7D%5Cright%5D)
→ nilai
=![\frac{1}{3.3-(-3).(-2)} \left[\begin{array}{ccc}3&-(-3)\\-(-2)&3\end{array}\right] \frac{1}{3.3-(-3).(-2)} \left[\begin{array}{ccc}3&-(-3)\\-(-2)&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3.3-%28-3%29.%28-2%29%7D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-%28-3%29%5C%5C-%28-2%29%263%5Cend%7Barray%7D%5Cright%5D)
=![\frac{1}{9-6} \left[\begin{array}{ccc}3&3\\2&3\end{array}\right] \frac{1}{9-6} \left[\begin{array}{ccc}3&3\\2&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B9-6%7D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%263%5C%5C2%263%5Cend%7Barray%7D%5Cright%5D)
=![\frac{1}{3} \left[\begin{array}{ccc}3&3\\2&3\end{array}\right] \frac{1}{3} \left[\begin{array}{ccc}3&3\\2&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%263%5C%5C2%263%5Cend%7Barray%7D%5Cright%5D)
=![\left[\begin{array}{ccc}\frac{3}{3} &\frac{3}{3} \\\frac{2}{3} &\frac{3}{3} \end{array}\right] \left[\begin{array}{ccc}\frac{3}{3} &\frac{3}{3} \\\frac{2}{3} &\frac{3}{3} \end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cfrac%7B3%7D%7B3%7D%20%26%5Cfrac%7B3%7D%7B3%7D%20%5C%5C%5Cfrac%7B2%7D%7B3%7D%20%26%5Cfrac%7B3%7D%7B3%7D%20%5Cend%7Barray%7D%5Cright%5D)
=![\left[\begin{array}{ccc}1&1\\\frac{2}{3} &1\end{array}\right] \left[\begin{array}{ccc}1&1\\\frac{2}{3} &1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%261%5C%5C%5Cfrac%7B2%7D%7B3%7D%20%261%5Cend%7Barray%7D%5Cright%5D)
→ nilai
=![\left[\begin{array}{ccc}2&2\\\frac{4}{3} &2\end{array}\right] \left[\begin{array}{ccc}2&2\\\frac{4}{3} &2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%262%5C%5C%5Cfrac%7B4%7D%7B3%7D%20%262%5Cend%7Barray%7D%5Cright%5D)
→ nilai det
=
=
=
=
14. C
=
=
=
=
=
=
=
sorry cuma bisa jawab 3, otak udh buntu:') udh ngantuk bangett, hehe
semoga membantu!