Mencari bilangan utama (a), dan rasio (r) dari barisan geometri:
U2= 12
U5= 4/9
U2= 12
U5= 4/9
Takamori37
![ar=12 \\ ar^4=\frac{4}{9} \\ --$Bagi$-- \\ r^{-3}=\frac{12}{\frac{4}{9}}=12\times\frac{9}{4}=27 \\ r^3=\frac{1}{27} \\ r=\sqrt[3]{\frac{1}{27}} \\ r=\frac{1}{3} \\ \\ ar=12 \\ a\times\frac{1}{3}=12 \\ a=36](https://tex.z-dn.net/?f=ar%3D12+%5C%5C+ar%5E4%3D%5Cfrac%7B4%7D%7B9%7D+%5C%5C+--%24Bagi%24--+%5C%5C+r%5E%7B-3%7D%3D%5Cfrac%7B12%7D%7B%5Cfrac%7B4%7D%7B9%7D%7D%3D12%5Ctimes%5Cfrac%7B9%7D%7B4%7D%3D27+%5C%5C+r%5E3%3D%5Cfrac%7B1%7D%7B27%7D+%5C%5C+r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7B27%7D%7D+%5C%5C+r%3D%5Cfrac%7B1%7D%7B3%7D+%5C%5C+%5C%5C+ar%3D12+%5C%5C+a%5Ctimes%5Cfrac%7B1%7D%7B3%7D%3D12+%5C%5C+a%3D36 "ar=12 \\ ar^4=\frac{4}{9} \\ --$Bagi$-- \\ r^{-3}=\frac{12}{\frac{4}{9}}=12\times\frac{9}{4}=27 \\ r^3=\frac{1}{27} \\ r=\sqrt[3]{\frac{1}{27}} \\ r=\frac{1}{3} \\ \\ ar=12 \\ a\times\frac{1}{3}=12 \\ a=36")
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Rosi28
makasih ya
