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(2x² - 9x + 9) = (2x-3)(x-3)
Faktorkan penyebut:
9-x² = -(x²-9)
9-x² = -(x+3)(x-3)
Sehingga:
lim_x⇒3 (2x²-9x+9)/(9-x²)
= lim_x⇒3 (2x-3)(x-3)/[-(x+3)(x-3)]
= lim_x⇒3 (2x-3)/-(x+3)
= - (2(3)-3)/(3+3)
= - (6-3)/9
= - 3/9
= - 1/3