[tex] \tt{ \frac{3}{2} + ( \frac{2}{5} \times \frac{3}{10} \div \frac{1}{9} ) } \\ [/tex]
[tex] \tt{ = \frac{3}{2} + ( \frac{1}{5} \times \frac{3}{5} \times \frac{9}{1} ) } \\ [/tex]
[tex] \tt{ = \frac{3}{2} + \frac{27}{25} } \\ [/tex]
[tex] \tt{ = \frac{75 + 54}{50} } \\ [/tex]
[tex] \tt \color{aqua}{ = \frac{129}{50} = 2 \frac{29}{50} } \\ [/tex]
[tex] \tt{ \frac{3}{2} - ( \frac{2}{5} \div \frac{3}{10} \times \frac{1}{9}) } \\ [/tex]
[tex] \tt{ = \frac{3}{2} - ( \frac{2}{5} \times \frac{10}{3} \times \frac{1}{9} ) } \\ [/tex]
[tex] \tt{ = \frac{3}{2} - ( \frac{2}{1} \times \frac{2}{3} \times \frac{1}{9} ) } \\ [/tex]
[tex] \tt{ = \frac{3}{2} - \frac{4}{27} } \\ [/tex]
[tex] \tt{ = \frac{81 - 8}{54} } \\ [/tex]
[tex] \tt \color{aqua}{ = \frac{73}{54} = 1 \frac{19}{54} } \\ [/tex]
Penjelasan dengan langkah-langkah:
[tex] \\ \\ \\ \\ \\ \\ \\ [/tex]
3/2 + (2/5 × 3/10 ÷ 1/9)
= 3/2 + (1/5 × 3/5 × 9/1)
= 3/2 + 27/5
= 75/50 + 54/50
= 129/50
= 2 29/50
[tex] \\ [/tex]
3/2 - (2/5 ÷ 3/10 × 1/9)
= 3/2 - (2/5 × 10/3 × 1/9)
= 3/2 - 4/27
= 81/54 - 8/54
= 73/54
= 1 19/54
[tex]\colorbox{black}{\purple{\boxed{\colorbox{black}{\purple{{Airacantika8}}}}}}[/tex]
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Nomor 1.
[tex] \tt{ \frac{3}{2} + ( \frac{2}{5} \times \frac{3}{10} \div \frac{1}{9} ) } \\ [/tex]
[tex] \tt{ = \frac{3}{2} + ( \frac{1}{5} \times \frac{3}{5} \times \frac{9}{1} ) } \\ [/tex]
[tex] \tt{ = \frac{3}{2} + \frac{27}{25} } \\ [/tex]
[tex] \tt{ = \frac{75 + 54}{50} } \\ [/tex]
[tex] \tt \color{aqua}{ = \frac{129}{50} = 2 \frac{29}{50} } \\ [/tex]
Nomor 2.
[tex] \tt{ \frac{3}{2} - ( \frac{2}{5} \div \frac{3}{10} \times \frac{1}{9}) } \\ [/tex]
[tex] \tt{ = \frac{3}{2} - ( \frac{2}{5} \times \frac{10}{3} \times \frac{1}{9} ) } \\ [/tex]
[tex] \tt{ = \frac{3}{2} - ( \frac{2}{1} \times \frac{2}{3} \times \frac{1}{9} ) } \\ [/tex]
[tex] \tt{ = \frac{3}{2} - \frac{4}{27} } \\ [/tex]
[tex] \tt{ = \frac{81 - 8}{54} } \\ [/tex]
[tex] \tt \color{aqua}{ = \frac{73}{54} = 1 \frac{19}{54} } \\ [/tex]
Penjelasan dengan langkah-langkah:
--
[tex] \\ \\ \\ \\ \\ \\ \\ [/tex]
Nomor 1 :
3/2 + (2/5 × 3/10 ÷ 1/9)
= 3/2 + (1/5 × 3/5 × 9/1)
= 3/2 + 27/5
= 75/50 + 54/50
= 129/50
= 2 29/50
[tex] \\ [/tex]
--
[tex] \\ [/tex]
Nomor 2 :
3/2 - (2/5 ÷ 3/10 × 1/9)
= 3/2 - (2/5 × 10/3 × 1/9)
= 3/2 - 4/27
= 81/54 - 8/54
= 73/54
= 1 19/54
[tex] \\ [/tex]
--
[tex] \\ [/tex]
[tex]\colorbox{black}{\purple{\boxed{\colorbox{black}{\purple{{Airacantika8}}}}}}[/tex]