Question

Hitunglah jumlah dari 1 + 1/3 + 1/9 .... sampai 6 suku

Answer 1

A = U1 = 1

r = U2/U1
r = (1/3)/1
r = 1/3

S6 = a . (1 - rⁿ)/(1 - r)
S6 = 1 . (1 - (1/3)⁶)/(1 - 1/3)
S6 = (1 - 1/729)/(3/3 - 1/3)
S6 = (729/729 - 1/729)/(2/3)
S6 = 728/729 × 3/2
S6 = 364/243

Answer 2

A=1
r = 1/3
r < 1

sn = a( 1 - rⁿ)/( 1- r)

s6 = 1 ( 1- 1/3⁶) /(1 - 1/3)
s6 = 1 (1 - 1/729) (2/3)
s6 = 3/2 (728/729)
s6 = 364/243