a)
[tex]a = 2^{4*7} = 2^{28}\\b = (-4)^{12} =4^{12} = (2^2)^{12} = 2^{24}\\\frac{a}{b} = 2^{28}/2^{24} = 2^4 = 16\\[/tex]
b)
[tex]a = (-9)^8 = 9^8 = (3^2)^8 = 3^{16} \\b= 3^{15}\\a/b = 3^{16}/3^{15} = 3[/tex]
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Verified answer
a)
[tex]a = 2^{4*7} = 2^{28}\\b = (-4)^{12} =4^{12} = (2^2)^{12} = 2^{24}\\\frac{a}{b} = 2^{28}/2^{24} = 2^4 = 16\\[/tex]
b)
[tex]a = (-9)^8 = 9^8 = (3^2)^8 = 3^{16} \\b= 3^{15}\\a/b = 3^{16}/3^{15} = 3[/tex]