Respuesta:
Explicación paso a paso:
[tex]\frac{8\times \frac{x^4}{y^3}-2xy}{4}xy[/tex]
[tex]=\frac{x\left(4x^3-y^4\right)}{2y^3}xy[/tex]
[tex]\mathrm{Multiplicar\:fracciones}:\quad \:a\times \frac{b}{c}=\frac{a\:\times \:b}{c}[/tex]
[tex]=\frac{x\left(4x^3-y^4\right)xy}{2y^3}[/tex]
[tex]=\frac{x^2y\left(4x^3-y^4\right)}{2y^3}[/tex]
[tex]\mathrm{Eliminar\:los\:terminos\:comunes:}\:y[/tex]
[tex]\frac{x^2\left(4x^3-y^4\right)}{2y^2}[/tex]
4×^5-×^2y^3/2y esa es la respuesta
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Verified answer
Respuesta:
✅ [tex]\frac{x^2\left(4x^3-y^4\right)}{2y^2}[/tex] ✅
Explicación paso a paso:
[tex]\frac{8\times \frac{x^4}{y^3}-2xy}{4}xy[/tex]
[tex]=\frac{x\left(4x^3-y^4\right)}{2y^3}xy[/tex]
[tex]\mathrm{Multiplicar\:fracciones}:\quad \:a\times \frac{b}{c}=\frac{a\:\times \:b}{c}[/tex]
[tex]=\frac{x\left(4x^3-y^4\right)xy}{2y^3}[/tex]
[tex]=\frac{x^2y\left(4x^3-y^4\right)}{2y^3}[/tex]
[tex]\mathrm{Eliminar\:los\:terminos\:comunes:}\:y[/tex]
[tex]\frac{x^2\left(4x^3-y^4\right)}{2y^2}[/tex]
✔✔ GRACIAS ✔✔
Respuesta:
4×^5-×^2y^3/2y esa es la respuesta