Question

810÷3³-4׳√27-(2⁸-3⁵)+2²​

Answer 1

RESOLVER:

[tex]\frac{810}{3^3}-4\sqrt[3]{27}-\left(2^6\left(-3\right)^5\right)+2^2[/tex]

Quitamos los paréntesis

[tex]=\frac{810}{3^3}-4\sqrt[3]{27}-2^6\left(-3\right)^5+2^2[/tex]

[tex]\frac{810}{3^3}:30[/tex]

[tex]4\sqrt[3]{27}:12[/tex]

[tex]2^6\left(-3\right)^5:-2^6\cdot \:3^5[/tex]

[tex]=30-12-\left(-2^6\cdot \:3^5\right)+2^2[/tex]

[tex]=30-12+2^6\cdot \:3^5+2^2[/tex]

[tex]30-12=18[/tex]

[tex]=2^6\cdot \:3^5+2^2+18[/tex]

[tex]2^6\cdot \:3^5:15552[/tex]

[tex]2^2:4[/tex]

[tex]=15552+4+18[/tex]

[tex]\boxed{=15574}[/tex]

[tex]Buena\:suerte\:con\:tus\:tareas\::ProfeAndresFelipe :)[/tex]