domslam sie ze zamiast = mial byc +, bo ta rownosc nie zachodzi, zatem
log3(1/9) * log3(1/81) + log3 81 =
log3(9)^(-1) * log3(81)^(-1) + 4 =
(-1)*log3(9) * (-1)*log3(81) + 4=
(-log3(9)) * (-log3(81)) + 4=
(-2) * (-4) +4 = 12
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Verified answer
domslam sie ze zamiast = mial byc +, bo ta rownosc nie zachodzi, zatem
log3(1/9) * log3(1/81) + log3 81 =
log3(9)^(-1) * log3(81)^(-1) + 4 =
(-1)*log3(9) * (-1)*log3(81) + 4=
(-log3(9)) * (-log3(81)) + 4=
(-2) * (-4) +4 = 12