Question

(Nomer 1) ∛3^((p+3)) = 1/ 81 √27^((2-2p))
(nomer 2) ^2 log x^2 = 1+ ^2 log (x+2)

Answer 1

Nomor1 

((3)^1/3)^p+3  = 1/3^4 ((3)^3)^2-2p
= 3^1/3p+1 = 1/3^4 (3^6-6p)
=3^1/3p+1 = 3^6-4-6p
= 3(1/3p + 1) = 3(2-6p)
= p+3 = 6 - 18p
= p+18p = 6-3
=19p = 3
= p= 3/19