Question

8 pangkat x + pangkat 2 = 0,125

Answer 1

8^(x+2)=0,125
x+2= ^8log 0,125
x+2=(^8log 0,125)
x+2=^8log 125/1000
x+2=^8log 1/8
x+2=^8log1 - ^8log 8
x+2=0-1
x+2=-1
x=-1-2
x=-3

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