Odpowiedź:
p=F/S
40dag=0.4kg
Fc=0.4kg*10m/s^2=4N
5cm=0.05m
Pole=0.05m*0.05m=0.0025m^2
4N/0.0025m^2=1600Pa=16hPa
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Odpowiedź:
p=F/S
40dag=0.4kg
Fc=0.4kg*10m/s^2=4N
5cm=0.05m
Pole=0.05m*0.05m=0.0025m^2
4N/0.0025m^2=1600Pa=16hPa