Respuesta:
[tex]\frac{\left(x-4\right)^2}{5^2}+\frac{\left(y-3\right)^2}{4^2}=1[/tex]
[tex]\mathrm{Por\:lo\:tanto,\:las\:propiedades\:de\:la\:elipse\:son:}\\\left(h,\:k\right)=\left(4,\:3\right),\:a=5,\:b=4[/tex]
[tex]\mathrm{Elipse\:con\:centro}\:\left(h,\:k\right)=\left(4,\:3\right),\:\:a=5,\:\:b=4[/tex]
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Respuesta:
[tex]\frac{\left(x-4\right)^2}{5^2}+\frac{\left(y-3\right)^2}{4^2}=1[/tex]
[tex]\mathrm{Por\:lo\:tanto,\:las\:propiedades\:de\:la\:elipse\:son:}\\\left(h,\:k\right)=\left(4,\:3\right),\:a=5,\:b=4[/tex]
[tex]\mathrm{Elipse\:con\:centro}\:\left(h,\:k\right)=\left(4,\:3\right),\:\:a=5,\:\:b=4[/tex]