Respuesta:
RESOLUCION
[tex](\frac{3}{4} +\frac{7}{25}) + (\frac{13}{50} -\frac{4}{8} )\\\\\frac{4}{8} = \frac{1}{2} \\\\(\frac{3}{4} +\frac{7}{25}) + (\frac{13}{50} -\frac{1}{2} )\\\\\frac{103}{100} +(\frac{13}{50} -\frac{1}{2} )\\\\\frac{103}{100} - \frac{6}{25} \\\\= \frac{79}{100}[/tex]
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Respuesta:
Hola ◬
RESOLUCION
[tex](\frac{3}{4} +\frac{7}{25}) + (\frac{13}{50} -\frac{4}{8} )\\\\\frac{4}{8} = \frac{1}{2} \\\\(\frac{3}{4} +\frac{7}{25}) + (\frac{13}{50} -\frac{1}{2} )\\\\\frac{103}{100} +(\frac{13}{50} -\frac{1}{2} )\\\\\frac{103}{100} - \frac{6}{25} \\\\= \frac{79}{100}[/tex]
Salu2!!