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a) dziesięciowodny siarczan (VI) sodu lub siarczan (VI) sodu - woda 1/10
b) Ba(OH)2 * 8H2O
Zadanie 2
MCo = 59u
MCl = 35,5u
MCoCl2 = 59u + 2*35,5u = 130u
MH2O = 2*1u + 16u = 18u
MCoCl2*6H2O = 130u + 6*18u = 238u